Asked by pheope
How many grams of bromine liquid are needed to make 6 moles of KBr?
Answers
Answered by
DrBob222
Br2(l) ==> 2KBr(s)
6 moles KBr x (1 mole Br2/2 moles KBr) = moles Br2
Then moles = grams/molar mass.
Substitute and solve for grams.
6 moles KBr x (1 mole Br2/2 moles KBr) = moles Br2
Then moles = grams/molar mass.
Substitute and solve for grams.
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