ok maybe this is clearer....
[40/(2+i)]-[35/(2-i)]
40 35
-
2+i 2-i
How do I solve this?
there is a division sign between the 40 and 2=i and another one between 35 and 2-i
2 answers
form the common denominator (2+i)(2-i) and
[40(2-i) -35(2+i)]/((2+i)(2-i))
= (80 - 40i - 70 - 35i)/(4-i^2)
=(10-75i)/5
= 2 - 15i
[40(2-i) -35(2+i)]/((2+i)(2-i))
= (80 - 40i - 70 - 35i)/(4-i^2)
=(10-75i)/5
= 2 - 15i