Asked by Ramesh Reddy
I will be very greatfull to you,if you help me to balance the below equations:
1.)NaOH+S gives rise to Na2S+S2O3+H2O
2.)Al(OH)3+3HCL gives rise to AlCl3+3H2O
1.)NaOH+S gives rise to Na2S+S2O3+H2O
2.)Al(OH)3+3HCL gives rise to AlCl3+3H2O
Answers
Answered by
DrBob222
Al(OH)3 + 3HCl ==> AlCl3 + 3H2O is already balanced.
I think you may have made a typo in the first one. I suspect it is S2O3^2- on the right which is the way I will balance it.
6NaOH + 4S ==> 2Na2S + Na2S2O3 + 3H2O
I think you may have made a typo in the first one. I suspect it is S2O3^2- on the right which is the way I will balance it.
6NaOH + 4S ==> 2Na2S + Na2S2O3 + 3H2O
Answered by
DrBob222
If you did not make a typo and it really is s2O3, then it is balanced as follows:
6NaOH + 5S ==> 3Na2S + S2O3 + 3H2O
6NaOH + 5S ==> 3Na2S + S2O3 + 3H2O
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