Asked by Gianina

Hector rain in the city charity race for four years. His times in minutes were: 14.8, 22.3 , 26.7, and 31.9 . What was his average time for the four years to the nearest tenth of a minute?

Answers

Answered by Ms. Sue
14.8 + 22.3 + 26.7 + 31.9 = ?

Divide the sum by 4 to find the average.

The answer to this problem is 24 because
14.8+22.3+26.7+31.9=23.925 and 23.925 to the nearest tenth is 24.
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