Find an equation of the plane through the point and perpendicular to the given vector.

Question

(7, 1, 5)
‹-3, 1, 2›

I think I need the normal vector, but how do I find it? And then what do I do?

Thank you.

Answer 1

The equation of this plane is

-3(x-7)+1(y-1)+2(z-5)=0 or

-3x+y+2z+10=0