Asked by lines & planes

Find an equation of the plane through the point and perpendicular to the given vector.
(7, 1, 5)
‹-3, 1, 2›

I think I need the normal vector, but how do I find it? And then what do I do?

Thank you.
Answered by Mgraph
The equation of this plane is

-3(x-7)+1(y-1)+2(z-5)=0 or

-3x+y+2z+10=0
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