A drag racer, starting from rest, speeds up for 402 m with an acceleration of +16.0 m/s2. A parachute then opens, slowing the car down with an acceleration of -5.60 m/s2. How fast is the racer moving 2.90 102 m after the parachute opens?

Question

A drag racer, starting from rest, speeds up for 402 m with an acceleration of +16.0 m/s2. A parachute then opens, slowing the car down with an acceleration of -5.60 m/s2. How fast is the racer moving 2.90  102 m after the parachute opens?

Henry · Accepted Answer

Vf^2 = Vo^2 + 2ad. Vf^2 = 0 + 2*16*402 = 12,864, Vf = 113.4m/s. Vf^2 = (113.4)^2 + 2*(-5.6)*290 = 9616, Vf = 98m/s.