Asked by marie s
a political discussion group consists of five Democrats and six Republicans. Four people are selected to attend a conference.
A.in how many ways can four people be selected from this group of eleven?
B.In how many ways can four Republicans be selected from six Republicans?
C.find the probability that the selected group will consist of all Republicans?
A.in how many ways can four people be selected from this group of eleven?
B.In how many ways can four Republicans be selected from six Republicans?
C.find the probability that the selected group will consist of all Republicans?
Answers
Answered by
deja
the answer is "C"
Answered by
marie s
Thanks, but i need the answer to all three questions
Answered by
Reiny
A) choose 4 from 11 which is C(11,4) or 330
b) choose 4 from 6 which is C(6,4) or 15
c) assuming that your group still consists of 4 people
prob = 15/330 = 1/22
b) choose 4 from 6 which is C(6,4) or 15
c) assuming that your group still consists of 4 people
prob = 15/330 = 1/22
Answered by
marie s
thank you
Answered by
drwls
A. 11 x 10 x 9 x 8/(4 x 3 x 2 x 1) = 330
B. 6!/(4!*2!) = 15
C. (6/11)*(5/10)*(4/9)*(3/8) = 0.04545
B. 6!/(4!*2!) = 15
C. (6/11)*(5/10)*(4/9)*(3/8) = 0.04545
Answered by
Anonymous
What is the cost of concrete for a walkway that is 15 feet long, 8 feet wide, and 9 inches deep if the concrete costs $30 per cubic yard?
Answered by
dick schweizer
$100
Answered by
Anonymous
2. To play the California lottery, a person has to correctly select 6 out of 51 numbers. What is the probability that one combination of six numbers will win? If it costs $1 to play and you receive $1,000,000 if you win, what is the expected value of the lottery?
Answered by
lay
A political discussion group consists of 6 Democrats and 10 Republicans. Five members are selected to attend a conference. Find the probability that the group will consist of all Democrats.