Asked by M
use dimensional analysis to find how many moles of nitrate ions are in 40.0 mL of a 0.75 M aqueous solution of aluminum nitrate
Answers
Answered by
DrBob222
I'll get you started.
(0.75 moles Al(NO3)3/L Al(NO3)3) x 0.040 L Al(NO3)3 = ??moles Al(NO3)3. Note that L Al(NO3)3 in the numerator cancel with L Al(NO3)3 in the denominator to leave moles Al(NO3)3. Now you need a factor to convert moles Al(NO3)3 to moles NO3^-.
(0.75 moles Al(NO3)3/L Al(NO3)3) x 0.040 L Al(NO3)3 = ??moles Al(NO3)3. Note that L Al(NO3)3 in the numerator cancel with L Al(NO3)3 in the denominator to leave moles Al(NO3)3. Now you need a factor to convert moles Al(NO3)3 to moles NO3^-.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.