Asked by Tania
Iam re-posting the following questions and would appreciate if anyone could show the working.
1]Find lim sinx/2x
x-->0
2]lim 3x^2-4x/7
x-->0
1]Find lim sinx/2x
x-->0
2]lim 3x^2-4x/7
x-->0
Answers
Answered by
Reiny
lim sinx/(2x) as x --> 0
= lim (1/2) sinx/x
= (1/2)(0) = 0
2. lim 3x^2 - 4x/7 as x --->0
= 0 - 0/7 = 0
= lim (1/2) sinx/x
= (1/2)(0) = 0
2. lim 3x^2 - 4x/7 as x --->0
= 0 - 0/7 = 0
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