Asked by Jess
Draw a rectangle with a perimeter of 58 m and an area of 120 m square
Answers
Answered by
Damon
2 x + 2 y = 58
x y = 120
2(120/y) + 2 y = 58
120/y + y = 29
y^2 - 29 y + 120 = 0
(y - 24)(y-5) = 0
y = 24 or y = 5
so I think it is length of 24 and width of 5
x y = 120
2(120/y) + 2 y = 58
120/y + y = 29
y^2 - 29 y + 120 = 0
(y - 24)(y-5) = 0
y = 24 or y = 5
so I think it is length of 24 and width of 5
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