Asked by Lina
Write your answer in standard form. Show all your work if you want to be eligible for partial credit.
Write the equation of a line perpendicular to the line y = (2/3)x - 7 and passing through the point (4,-2).
The slope of the line y = (2/3)x - 7 is 2/3. The slope of a line perpendicular to this line must be its negative reciprocal, or -3/2.
Using the point-slope form to find the other line:
y - y1 = m(x - x1)
y - (-2) = -3/2(x - 4)
y + 2 = (-3/2)x + 6
y = (-3/2)x + 4
In standard form:
(3/2)x + y = 4
Write the equation of a line perpendicular to the line y = (2/3)x - 7 and passing through the point (4,-2).
The slope of the line y = (2/3)x - 7 is 2/3. The slope of a line perpendicular to this line must be its negative reciprocal, or -3/2.
Using the point-slope form to find the other line:
y - y1 = m(x - x1)
y - (-2) = -3/2(x - 4)
y + 2 = (-3/2)x + 6
y = (-3/2)x + 4
In standard form:
(3/2)x + y = 4
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