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Here is one of the simplest formulas for finding Pythagorean triples
if m and n are integers such that m>n
then
m^2 + n^2
m^2 - n^2 and
2mn
will form a Pythagorean triples.
e.g. let m= 7, n = 2
m^2+n^2 = 49+4 = 53
m^2-n^2 = 49-4 = 45
2mn = 2(7)(2) = 28
check: 53^2 = 2809
28^2+45^2 = 784+2025 = 2809
You can do 4 more like that.