Asked by John
Can anyone please help me with this? Can anyone please build or generate at least five Pythagorean Triples using one of the many formulas available online. Then After building the triples, verify each of them in the Pythagorean Theorem equation. Thank you so very much.
Answers
Answered by
Reiny
Here is one of the simplest formulas for finding Pythagorean triples
if m and n are integers such that m>n
then
m^2 + n^2
m^2 - n^2 and
2mn
will form a Pythagorean triples.
e.g. let m= 7, n = 2
m^2+n^2 = 49+4 = 53
m^2-n^2 = 49-4 = 45
2mn = 2(7)(2) = 28
check: 53^2 = 2809
28^2+45^2 = 784+2025 = 2809
You can do 4 more like that.
if m and n are integers such that m>n
then
m^2 + n^2
m^2 - n^2 and
2mn
will form a Pythagorean triples.
e.g. let m= 7, n = 2
m^2+n^2 = 49+4 = 53
m^2-n^2 = 49-4 = 45
2mn = 2(7)(2) = 28
check: 53^2 = 2809
28^2+45^2 = 784+2025 = 2809
You can do 4 more like that.
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