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A person with skin area 2 m2 and 0.97 radiation efficiency is at rest and has a skin temperature of 28 C in an environment with...Asked by KAIT
a. A person with skin area 2 m2 and 0.97 radiation efficiency is at rest and has a skin temperature of 28 C in an environment with a uniform temperature of 22 C
Calculate the heat loss rate in watts
Calculate the heat loss rate in watts
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Answered by
qwerty123
Heat loss rate= q/t= (0.97(2)(28-22))/ thickness of skin.
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