Asked by Matt
Given: 2N2(g) +O(2) --> 2N2O(g) Kc =1.2x10^(-35)
N2O4(g) --> 2NO2(g) Kc = 4.6x10^(-3)
1/2N2(g) + O2(g) --> NO2(g) Kc= 4.1x10^(-9)
Calculate Kc for the reaction between one mole of dinitrogen oxide gas and oxygen gas to give nitrogen tetroxide gas.
N2O4(g) --> 2NO2(g) Kc = 4.6x10^(-3)
1/2N2(g) + O2(g) --> NO2(g) Kc= 4.1x10^(-9)
Calculate Kc for the reaction between one mole of dinitrogen oxide gas and oxygen gas to give nitrogen tetroxide gas.
Answers
Answered by
Matt
I got 1054.9 as my answer. I reversed the first eq and did (1/K1^(1/2)) added it to reverse of second eq (1/K2) then added that to the 3rd eq times 2 (K3^2). This got me the right equation. Do I just multiply the new Kc values together to get the final Kc of the new equation?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.