Asked by lizzie
Solve the following system using substitution:
y = x + 2
y = 3x
I don't understand this question.
y = x + 2
y = 3x
I don't understand this question.
Answers
Answered by
drwls
Substitute 3x for y in the first equation.
That leaves you with
3x = x + 2
which can be rewritten
2x = 2
Solve that for x.
Then, knowing x, use either equation to get y.
That leaves you with
3x = x + 2
which can be rewritten
2x = 2
Solve that for x.
Then, knowing x, use either equation to get y.
Answered by
lizzie
Answer (1,3)
Answered by
drwls
Yes, that is the answer. x = 1 and y = 3
Answered by
lizzie
Simplify (d^4)(d^5)^3.
Is it d^27
Is it d^27
Answered by
drwls
Yes
Answered by
lizzie
Sum of the solutions to
x2 - 3x - 18 = 0
Is it -3 ?
x2 - 3x - 18 = 0
Is it -3 ?
Answered by
Reiny
no,
for ax^2 + bx + c = 0, the sum of the roots is -b/a
so the sum is -(-3) = +3
for ax^2 + bx + c = 0, the sum of the roots is -b/a
so the sum is -(-3) = +3
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