Question

Some hydrogen gas is enclosed within a chamber being held at 200C with a volume of 0.025m^3. The chamber is fitted with a movable piston. Initially, the pressure in the gas is 1.50*10^6 Pa (14.8 atm). The piston is slowly extracted until the pressure in the gas falls to 0.95 * 10^6 Pa. What is the final volume V_2 of the container? Assume that no gas escapes and that the temperature remains at 200C.

How do you set this up? I know you use pV=nRT but the double pressure thing kinda throws me off

Answer 1

I got the above question correct, but this next one is the one I need help with:

Some hydrogen gas is enclosed within a chamber being held at 200C whose volume is 0.025m^3. Initially, the pressure in the gas is 1.50 * 10^6 Pa (14.8 atm). The chamber is removed from the heat source and allowed to cool until the pressure in the gas falls to 0.95 * 10^6 Pa. At what temperature T_2 does this occur?

Answer 2

since the temp is constant use p1v1=p2v2

Answer 3

no