Asked by Anon
A student walks around a pool and estimates the pool has a circumference of 240 m.
Using a protractor the students gages the angle of elevation to the top of the fountain, in the center of the pool, to be 74 degrees.
Using a protractor the students gages the angle of elevation to the top of the fountain, in the center of the pool, to be 74 degrees.
Answers
Answered by
drwls
This question in incomplete. Do they want to know the height of the fountain?
That would be H = R*tan74, where
R = 240/(2 pi) = 38.2 meters.
Now compute H.
It seems rather high to me.
That would be H = R*tan74, where
R = 240/(2 pi) = 38.2 meters.
Now compute H.
It seems rather high to me.
Answered by
Anon
Oh, yes. I am sorry.
I am attempting to calculate the height of the fountain.
It does indeed seem rather high. But the numbers for my assignment are randomly generated. So that may explain this phenomenon.
Thank you for your help.
I am attempting to calculate the height of the fountain.
It does indeed seem rather high. But the numbers for my assignment are randomly generated. So that may explain this phenomenon.
Thank you for your help.
Answered by
Henry
So what is your question? I'm assuming
you want to know the height of the fountain.
C = 6.28r = 250m,
r = 250 / 6.28 = 39.8m.
tan74 = h/r = h / 39.8
h = 39.8tan74 = 138.8m.
you want to know the height of the fountain.
C = 6.28r = 250m,
r = 250 / 6.28 = 39.8m.
tan74 = h/r = h / 39.8
h = 39.8tan74 = 138.8m.
Answered by
Henry
drwls, you finished a little ahead of me: but that's good because i used the wrong value for the circumference.
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