Asked by Henry
what is the pH of a 0.025 M aqueous solution of sodium propionate, NaC3H5O2? What is the concentration of propionic acid in the solution?
Answers
Answered by
DrBob222
This is a hydrolysis problem. The sodium propionate ion (which I'll call Pr^-) hydrolyzes.
Pr^- + HOH ==> HPr + OH^-
Set up an ICE chart and substitute into the Kb expression for Pr^-. (HPr is propionic acid).
Kb = (Kw/Ka) = (HPr)(OH^-)/(Pr^-).
(HPr_ = x = (OH^-). (Pr^-) = 0.025M from the problem. Solve for x and convert to pH. Post your work if you get stuck.
Pr^- + HOH ==> HPr + OH^-
Set up an ICE chart and substitute into the Kb expression for Pr^-. (HPr is propionic acid).
Kb = (Kw/Ka) = (HPr)(OH^-)/(Pr^-).
(HPr_ = x = (OH^-). (Pr^-) = 0.025M from the problem. Solve for x and convert to pH. Post your work if you get stuck.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.