Ag(s) + Cl2(g) --> 2AgCl(s)

Question

∆H and ∆S are 254.14kJ and –115.0J/K respectively. Calculate equilibrium constant, K for the reaction at 500K?

Answer 1

K = e^(-∆S/R*T) = e^(-(-115.0J/K)/(8.314J/K*mol)*500K) = 1.9 x 10^-3