What is the pH of a solution in which 296 mL of HCl measured at 28.0 C and 1.02 atm, is dissolved in 1.5 L of aqueous solution?

Answer 1

You don't say but I assume the 296 mL HCl is a GAS. Then use PV = nRT and solve for n. Then M HCl = moles HCl/1.5L. Finally, pH = -log(H^+) and M HCl = H^+.

Answer 2

I plugged in all my numbers but I am still stuck on how to find n:moles

Answer 3

296mL is the volume