Asked by Henry
if the rms speed of NH3 molecules is found to be 0.510 km/s what is the temperature (in Celcius)?
can someone solve this using the formula
c=((2.55*R*T)/M)^1/2
c is the speed
r is 8.314 constant
M is the molar mass of NH3 17.031
can someone solve this using the formula
c=((2.55*R*T)/M)^1/2
c is the speed
r is 8.314 constant
M is the molar mass of NH3 17.031
Answers
Answered by
Henry
btw i know the answer is -96 degrees C from the back of the book but i just wanna know how to get this answer
Answered by
DrBob222
Here is what I would do.
u = sqrt(3RT/M)
u^2 = 3RT/M
510^2*M = 3RT
T = 510^2*M/3R
T = 510^2*0.01703/3*8.314
<b>M is in kg</b>
T = 177.59 K - 273.15 = -95.56
which rounds to -96 C.
I don't know where your 2.55 came from.
u = sqrt(3RT/M)
u^2 = 3RT/M
510^2*M = 3RT
T = 510^2*M/3R
T = 510^2*0.01703/3*8.314
<b>M is in kg</b>
T = 177.59 K - 273.15 = -95.56
which rounds to -96 C.
I don't know where your 2.55 came from.
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