Given that ΔHof of copper (II) chloride, CuCl2(s), is –220.1/kJ and ΔHof of copper (I) chloride, CuCl(s), is –137.2 kJ, calculate ΔHo for the reaction when 14.0 g of copper is used:

Question

CuCl2(s) + Cu(s) → 2 CuCl(s)

Answer 1

DHfrxn = (n*DHfproducts)-(n*DHfreactants)

This is for 1 mol Cu.
DHfrxn x 14 g Cu/atomic mass Cu = ??