Ask a New Question
Search
factorize a^3+b^3+c^3-3abc
1 answer
abc(a^2bc+ab^2c+abc^2-3) =
abc(abc(a+b+c)-3).
Similar Questions
Key: logx= log base x
1. Prove that: (logx64 +logx4 -logx8)/(logx1024) =1/2 2.factorize by grouping r^2s^2+3t^2+r^2t^2+3s^2
1 answer
(a+b)^3+(b+c)^3+(c+a)^3-3(a-b)(b-c)(c-a)=2(a^3+b^3+c^3-3abc)
1 answer
2a^3+2b^3+2c^3-3abc=?
1 answer
(6a^b)^3 x (1/3abc)^2
1 answer
more similar questions