Asked by Luc
A car of mass 1200kg travelling @ 72 km/h is brought to rest in 4s.Find a) the average deceleration b)the average braking force
Answers
Answered by
drwls
a) 72 km/h = 20 m/s
Deceleration = 20/4 = 5 m/s^2
b) Momentum change = Avg. Force * Time
Solve for the Average Force
Deceleration = 20/4 = 5 m/s^2
b) Momentum change = Avg. Force * Time
Solve for the Average Force
Answered by
Laziy bee montengro jr
a) Deceleration is -5
b) Average braking force -6000
b) Average braking force -6000
Answered by
Moko
15000N
Answered by
hussein ahmed
A 5m\s B 6000
Answered by
Nyakundi
Deceleration =5m/s^2
Force=6000N
Force=6000N
Answered by
Floriana
72km/h=20m/s
20/4
=5m/s
20/4
=5m/s
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