Asked by ROCKY
Given the quadraticf(x)=x^2-14x+49, find a value of x such thatf(x)=36
Answers
Answered by
Damon
36 = x^2 -14 x + 49
x^2 -14 x + 13 = 0
(x-13)(x-1) = 0
x = 13 or x = 1
x^2 -14 x + 13 = 0
(x-13)(x-1) = 0
x = 13 or x = 1
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