Asked by Meghan
Bacteria experiences exponential growth, increasing 17% every hour. If there are 800 bacteria now, in how many hours will there be 2000? How would I go about this problem?
Answers
Answered by
Damon
dx/dt = .17x
dx/x = .17 dt
ln x = .17t + C
x = e^(.17t+C) = e^C e^.17t
when t = 0
800 = e^C e^0 = e^C
so
x = 800 e^.17t
2000 = 800 e^.17t
2.5 = e^.17 t
ln 2.5 = .17 t
t = .916/.17 = 5.39 hr
dx/x = .17 dt
ln x = .17t + C
x = e^(.17t+C) = e^C e^.17t
when t = 0
800 = e^C e^0 = e^C
so
x = 800 e^.17t
2000 = 800 e^.17t
2.5 = e^.17 t
ln 2.5 = .17 t
t = .916/.17 = 5.39 hr
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