Asked by bethy
how would you solve for x in a 45-45-90 triangle if the hypotenuse is 9 square root 2
Answers
Answered by
Reiny
I assume x is the value of the other sides, (they are equal)
the ratio of sides in a 45-45-90 triangle is 1:1:√2
so x/1 = 9√2/√2
x = 9
check: 9^2 + 9^2= h^2
h^2 = 162
h = √162 = 9√2
the ratio of sides in a 45-45-90 triangle is 1:1:√2
so x/1 = 9√2/√2
x = 9
check: 9^2 + 9^2= h^2
h^2 = 162
h = √162 = 9√2
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