Asked by Jennifer
A theater purchases $500 worth of Sticky Bears and chocolate bombs. Each bag of Sticky Bears costs $1.50 and each bag of Chocolate Bombs costs $1.00. If a total of 400 bags of candy were purchased, how many bags of Chocolate Bombs did the theater buy?
Answers
Answered by
MathMate
Let
S=number of bags of sticky bears, then
400-S=number of bags of chocolate bombs.
From total cost = $500, we get
1.5S+1.0(400-S)=500
Solve for S
0.5S = 500-400
S=200
Quick way:
each bag of sticky bears costs 1.50
each bag of chocolate costs 1.00
Average cost = $500/400=1.25
which is smack in between 1.00 and 1.50.
So equal number of bags of each, namely 200.
S=number of bags of sticky bears, then
400-S=number of bags of chocolate bombs.
From total cost = $500, we get
1.5S+1.0(400-S)=500
Solve for S
0.5S = 500-400
S=200
Quick way:
each bag of sticky bears costs 1.50
each bag of chocolate costs 1.00
Average cost = $500/400=1.25
which is smack in between 1.00 and 1.50.
So equal number of bags of each, namely 200.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.