Asked by Jen
Evaluate: 7^C4
i think its something like:
(7*6*5*4*3*2*1) / ((2*1)(4*3*2*1)) = (7*6*5*4)/(4*3*2*1) = (7*6*5)/(2*1) = 105...did i do i right??
i think its something like:
(7*6*5*4*3*2*1) / ((2*1)(4*3*2*1)) = (7*6*5*4)/(4*3*2*1) = (7*6*5)/(2*1) = 105...did i do i right??
Answers
Answered by
Damon
Oh, you mean combinations
7!/[ 4!(7-4)!]
7! / [4!*3!]
7*6*5/3!
7*6*5/(3*2)
7*5
35
7!/[ 4!(7-4)!]
7! / [4!*3!]
7*6*5/3!
7*6*5/(3*2)
7*5
35
Answered by
Reiny
You are still writing the notation incorrectly, there is no exponent.
<sub>7</sub>C<sub>4</sub> is what you want
also written as C(7,4)
the value is
7!/(4!3!) = 7*6*5/(3*2) = 35
or 5040/(24*6) = 35
<sub>7</sub>C<sub>4</sub> is what you want
also written as C(7,4)
the value is
7!/(4!3!) = 7*6*5/(3*2) = 35
or 5040/(24*6) = 35
Answered by
Jen
i know i just don't know how to input it correctly on my computer :(
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