Asked by basit shah
ten bricks each 6.0cm thick and mass of 1.5kg, lie on a table, how much work is required to stack them one on the top of another?
A. 40j
B. 88j
C. 45j
D. 0j
E. None of these
A. 40j
B. 88j
C. 45j
D. 0j
E. None of these
Answers
Answered by
Damon
original height of center of mass = 3 cm
final height of center of mass = 5^6 = 30cm
change in height of GC = 30-3 = 27 cm=.27m
work = m g h = 15 * 9.8 * .27 = 39.69 or 40 J so A
final height of center of mass = 5^6 = 30cm
change in height of GC = 30-3 = 27 cm=.27m
work = m g h = 15 * 9.8 * .27 = 39.69 or 40 J so A
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