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Asked by danielle

use law of sines t solve the triangle A=5degree 40', B=8degree 15', b=4.8
14 years ago

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Answered by Reiny
angle C = 166° 5'

b/sin5°40" = 4.8/sin8°15'
b = 3.303

c/sin166°5' = 4.8/sin8°15'
c = 8.045
14 years ago
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use law of sines t solve the triangle A=5degree 40', B=8degree 15', b=4.8

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