Asked by KEViN
A country's population in 1991 was 15 million. In 2001 it was 16 million. Estimate the population in 2005 using exponential growth formula. Round your answer to the nearest million.
Answers
Answered by
Reiny
let N = 15 e^(kt), where N is in million, t is in years since 1991 and k is a constant
when t = 10 , N = 16
16 = 15e^(10k)
1.0666667 = e^(10k)
ln 1.0666667 = 10k
k = .006456852
then when t = 14
N = 15e^(14(.00645852)) = 16.418
So to the nearest million it would still be 16 million
when t = 10 , N = 16
16 = 15e^(10k)
1.0666667 = e^(10k)
ln 1.0666667 = 10k
k = .006456852
then when t = 14
N = 15e^(14(.00645852)) = 16.418
So to the nearest million it would still be 16 million
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