Asked by Kate
Use the information provided to write the vertex form equation of each parabola.
a)y + 60x + 294 = -3x^2
b)−(y+1) = (x−4)^2
a)y + 60x + 294 = -3x^2
b)−(y+1) = (x−4)^2
Answers
Answered by
Henry
a. y = -3x^2 -60x - 294.General or STD Form.
h = -b/2a = 60 / -6 = -10.
k = -3(-10)^2 - 60*-10 - 294 = 6.
y = a(x-h)^2 + k,
y = -3(x+10)^2 + 6. Vertex Form.
b. -(y+1) = (x-4)^2,
-y-1 = x^2 - 8x + 16,
-y = x^2 - 8x + 17,
y = -x^2 + 8x - 17,
h = -b/2a = -8 / -2 = 4.
k = -(4)^2 +8*4 - 17 = -1.
y = -(x-4)^2 - 1.
h = -b/2a = 60 / -6 = -10.
k = -3(-10)^2 - 60*-10 - 294 = 6.
y = a(x-h)^2 + k,
y = -3(x+10)^2 + 6. Vertex Form.
b. -(y+1) = (x-4)^2,
-y-1 = x^2 - 8x + 16,
-y = x^2 - 8x + 17,
y = -x^2 + 8x - 17,
h = -b/2a = -8 / -2 = 4.
k = -(4)^2 +8*4 - 17 = -1.
y = -(x-4)^2 - 1.
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