Asked by Lynda
______
/b2-4ac; b=3, a=-1, c=-2
What would the solution be?
/b2-4ac; b=3, a=-1, c=-2
What would the solution be?
Answers
Answered by
Anonymous
b^2-4ac=9-8=1
X1=(-b-sqrt(1))/2a=(-3-1)/(-2)=2
X2=(-b+sqrt(1))/2a=(-3+1)/(-2)=1
X1=(-b-sqrt(1))/2a=(-3-1)/(-2)=2
X2=(-b+sqrt(1))/2a=(-3+1)/(-2)=1
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