Asked by Henry

How many milliliter of 0.150 M H2SO4 (sulfuric acid) are required to react with 1.87 g of sodium hydrogen carbonate, NaHCO3, according to the following equation?
H2SO4 + 2NaHCO3 --> Na2SO4 + 2H2O + 2CO2

dont understand this am i suppose to change 1.87 into Molarity for liters or something?? never learned how to do that
thanks for the comments in advance
Answered by DrBob222
A step by step procedure for working these problems.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Answered by Henry
@DrBob222 the link you provided doesnt do a good job in explaining how to convert grams into liters/Molarity
if you can do u think u can go into a little more detail on showing me what to do with the 1.87 sodium hydrogen carbonate?
thanks
Answered by DrBob222
Grams don't convert to liters or to molarity.. Grams converts to moles. moles = grams/molar mass. Then you use the equation to convert moles of one material to moles of the other. If you have M and L, then moles = M x L.
So just follow the steps.
Convert 1.87 grams NaHCO3 to moles. moles = grams/molar mass.
2. You have moles NaHCO3, now convert that to moles H2SO4 using the coefficients in the balanced equation.
3. Now you have moles H2SO4. M x L = moles. You have moles and M from the problem, solve for L and convert to mL.
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