find the eqt. of tangent to the curve y=-x^2+2x-10 @ the point where the curve cuts the y-axis.[ans:y=2x-10]

Question

how do i do this because they didn't give me the point...?

Answer 1

Yes, they did
It said, "where the curve cuts the y-axis", that is when x = 0
when x=0, y = -0 + 0 - 10 = -10
so your point is (0,-10)

drwls answered this for you already, did you not read it?
http://www.jiskha.com/display.cgi?id=1311337279