Asked by stephanie
suppose 5.00g of sodium carbonate reacts completely with excess of hydrochloric acid. Show how to calculate the mass (g) of sodium chloride that would be formed.
Na2CO3 + 2HCl = 2NaCl + CO2 + H2O
What is the limiting reagent?
Na2CO3 + 2HCl = 2NaCl + CO2 + H2O
What is the limiting reagent?
Answers
Answered by
bobpursley
how many moles of sodium carbonate is in 5 grams? From the balanced equation, one gets twice that number of moles of sodium chloride. That number can be converted to grams of sodium chloride.
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