Asked by Pappi
If velocity v of particle moving in straight line is related with distance travelled S as v=2(1+S)^1/2. What will the acceleration of the particle?
Answers
Answered by
bobpursley
The problem I have here is units.
velocity is distance/time, and your equation is sqrt distance. Hmmmm.
Assuming somehow that is fixed in magic land, then
acceleration= dv/dt=
(1+s)^-1/2 * ds/dt but ds/dt is V so
acceleration= 2 (1+s)^0=2
velocity is distance/time, and your equation is sqrt distance. Hmmmm.
Assuming somehow that is fixed in magic land, then
acceleration= dv/dt=
(1+s)^-1/2 * ds/dt but ds/dt is V so
acceleration= 2 (1+s)^0=2
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