Asked by calisha
Find the vertex angle of an isosceles triangle with base angles of (3x+10) and (8x-15). Show your work for credit.
Answers
Answered by
Reiny
So the two base angles must be equal
8x - 15 = 3x + 10
5x = 25
x = 5
so each of the base angles is 25°
That would leave 130° for your vertex angle
(25+25+130=180)
8x - 15 = 3x + 10
5x = 25
x = 5
so each of the base angles is 25°
That would leave 130° for your vertex angle
(25+25+130=180)
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