Re-post
? [H3O+] in 0.15 M C2N2H8
and 0.35 M C2H2H9Cl; Kb= 4.7 x 10^-4
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I don't know what those empirical formulas stand for but one is an acid and the other a base. Use the Henderson-Hasselbalch equation, solve for pH and convert to H3O^+.
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