Question

The reaction of calcium bicarbonate, Ca(HCO3)2 with hydrochloric acid, HCl, produces a solution of CaCl2, gaseous carbon dioxide, CO2, and water, H2O. Write a balanced chemical equation for this reaction and determine the volume of CO2, in mL, that forms at 30.0 oC and 0.660 atm upon reacting 40.3 mL of 0.200 M Ca(HCO3)2 with excess HCl.

Answer 1

I. balanced equation:
Ca(HCO3)2 + HCl ->CaCl2 + 2 H2O + 2 CO2

II. find moles of Ca(HCO3)2 :

40.3 mL x 1 L/1000mL x 0.2 mole/L =
8.06 x 10^-3 moles Ca(HCO3)2

III. find moles CO2 :
[8.06 x 10^-3] moles Ca(HCO3)2 x
2 moles CO2/1 mole Ca(HCO3)2 =
1.61 x 10^-2 moles CO2

IV. find volume from PV=nRT
V= nRT/P
V = (1.61 x10^-2)(0.082)(273 +30)
all divided by 0.660) = 0.606 L =606 mL