Asked by Anonymous
log_5[log_4(log_3(x))] = 1
log_5 = log with the base of 5
log_4 = log with the base of 4
log_3 = log with the base of 3
Answer: 3^1024
Too many logs in one equation. . .I don't know how to solve it
log_5 = log with the base of 5
log_4 = log with the base of 4
log_3 = log with the base of 3
Answer: 3^1024
Too many logs in one equation. . .I don't know how to solve it
Answers
Answered by
Damon
5^log_5[log_4(log_3(x))] = [log_4(log_3(x))] =5^1
4^log_4(log_3(x))= (log_3(x))=4^5 = 1024
3^log_3(x) =x =3^1024
4^log_4(log_3(x))= (log_3(x))=4^5 = 1024
3^log_3(x) =x =3^1024
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