Asked by josh
A space shuttle orbits at an altitude of approximately 200km above the surface of the Earth. If the radius of the Earth itself is 6380 km, what’s the acceleration due to gravity at the altitude of the space shuttle?
Answers
Answered by
drwls
It is 9.81 m/s^2, multiplied by an inverse square law term,
(6380/6580)^2,
to accounnt for the reduction with increased distance from the center of the earth.
g' = 9.81*0.940 = 9.22 m/s^2
(6380/6580)^2,
to accounnt for the reduction with increased distance from the center of the earth.
g' = 9.81*0.940 = 9.22 m/s^2
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