Asked by Edward
A race car is able to accelerate at a rate of 14m/s2. After exiting a turn at a speed of 15m/s, the car enters a straightaway and accelerates to a speed of 96m/s just as it reaches the end of the straightaway and enters the next turn.
A)how long did it take the car to accelerate to 96m/s.
b) how long is the straightaway, from the point where the car began accelerating the to point where it entered the next turn?
A)how long did it take the car to accelerate to 96m/s.
b) how long is the straightaway, from the point where the car began accelerating the to point where it entered the next turn?
Answers
Answered by
Henry
a. Vf = Vo + at,
t = (Vf-Vo)/a = (96-15) / 14 = 5.79s.
b. Vf^2 = Vo^2 + 2ad,
d = (Vf^2-Vo^2)/2a,
d = (9216-225) / 28 = 321m.
t = (Vf-Vo)/a = (96-15) / 14 = 5.79s.
b. Vf^2 = Vo^2 + 2ad,
d = (Vf^2-Vo^2)/2a,
d = (9216-225) / 28 = 321m.
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