Asked by Josh
No its not a typo but I did put the wrong activation energy. Its suppose to be a certain reaction has an activation energy of 37.70kj/mol. At what kelvin temperature will the reaction proceed 3.00 times then it did at 303k?
I was working the problem and got stuck on finishing the equation 1/T2=1/303k-1.099/4534.25k?
I was working the problem and got stuck on finishing the equation 1/T2=1/303k-1.099/4534.25k?
Answers
Answered by
DrBob222
http://www.jiskha.com/display.cgi?id=1310866247
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