Asked by John
Given the funtion G(t) = t2 - 7t + 5, evaluate G(-1+h)-G(-1)/h
Answers
Answered by
Reiny
g(-1+h) = (-1+h)^2 - 7(-1+h) + 5
= 1 - 2h + h^2 + 7 - 7h + 5
= h^2 - 9h + 13
g(-1) = 1 + 7 + 5 = 13
( g(-1+h) - g(-1) )/h = (h^2 - 9h + 13 - 13)/h
= h - 9
= 1 - 2h + h^2 + 7 - 7h + 5
= h^2 - 9h + 13
g(-1) = 1 + 7 + 5 = 13
( g(-1+h) - g(-1) )/h = (h^2 - 9h + 13 - 13)/h
= h - 9
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