Asked by Josh

The rate constant for this first order reaction is 0.0470 s-1 at 400 C.

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After how many seconds will 11.0% of the reactant remain?

Answers

Answered by DrBob222
This is the long way around but this is what I would do.
ln(No/N) = kt
I would call No = 100
Then N would be 11.
Substitute k and solve for t in seconds.
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