Asked by Anonymous
x^+8x+20 as a perfect square plus a constant then sketch the graph
Answers
Answered by
bobpursley
I assume you meant x^2
(x^2+8x+16)+4
(x+4)^2+4
(x^2+8x+16)+4
(x+4)^2+4
Answered by
Bosnian
Some quadratics can be factored into two identical binomials. These quadratics are called perfect square trinomials. Perfect square trinomials can be factored as follows:
a^2+2ab+b^2=(a+b)^2
OR
a^2-2ab+b^2=(a-b)^2
In this case:
a=1
2ab=8
2*1*b=8
2b=8 Diwide both sides with 2
b=4
(x+4)^2=x^2+2*x*4+4^2
(x+4)^2=x^2+8x+16
x^+8x+20 = x^2+8x+16+4 = (x+4)^2+4
Graph:
In google type:
functions graphs online
When you see list of results click on:
rechneronline.de/function-graphs/
When page be open in blue rectangle type:
Range x-axis from
In displayproperties type:
Range x-axis from -10 to 10
Range y-axis from -1 to 19
and click option Draw
You also can calculate values of expresion:
x^+8x+20 = (x+4)^2+4
x= -10
(x+4)^2+4=(-10+4)^2+4=(-6)^2+4=36+4=40
x= -9
(x+4)^2+4=(-9+4)^2+4=(-5)^2+4=25+4=29
x= -8
(x+4)^2+4=(-8+4)^2+4=(-4)^2+4=16+4=20
etc.
a^2+2ab+b^2=(a+b)^2
OR
a^2-2ab+b^2=(a-b)^2
In this case:
a=1
2ab=8
2*1*b=8
2b=8 Diwide both sides with 2
b=4
(x+4)^2=x^2+2*x*4+4^2
(x+4)^2=x^2+8x+16
x^+8x+20 = x^2+8x+16+4 = (x+4)^2+4
Graph:
In google type:
functions graphs online
When you see list of results click on:
rechneronline.de/function-graphs/
When page be open in blue rectangle type:
Range x-axis from
In displayproperties type:
Range x-axis from -10 to 10
Range y-axis from -1 to 19
and click option Draw
You also can calculate values of expresion:
x^+8x+20 = (x+4)^2+4
x= -10
(x+4)^2+4=(-10+4)^2+4=(-6)^2+4=36+4=40
x= -9
(x+4)^2+4=(-9+4)^2+4=(-5)^2+4=25+4=29
x= -8
(x+4)^2+4=(-8+4)^2+4=(-4)^2+4=16+4=20
etc.
Answered by
Bosnian
rechneronline.de/function-graphs/
IN BLUE RECTANGLE TYPE:
(x+4)^2+4
IN BLUE RECTANGLE TYPE:
(x+4)^2+4
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.