Asked by Jon
Hi I need someone to check my answers I'll show whatever work I have but for time purposes I'll just post my answers because I think I have most of them correct. Thanks!
1)Find the 20th term of the arithmetic sequence in which a1=3 and d=7.
A)143
B)136
C)140
D)133
I chose B
2)Write an equation for the nth term of the arithmetic sequence -3,3,9,15...
A)aN=n+6
B)aN=6n+9
C)aN=6n-9
D)aN=n-3
I chose B
3)Find the two arithmetic means between 4 and 22.
A)10,16
B)8,16
C)8,12
D)13,13
I chose A
4)Simplify: Find Sn for the arithmetic series in which a1=3,d=1/2,and aN=15
A)225
B)9
C)45
D)210
I chose B
5)ok this one's tricky to type but its with sigma so here it is.
There is a sigma sign and there is an 8 on the top of it and k=3 below. In parentheses to the right is (40-3k) and the question is Find.
A)45
B)282
C)-90
D)141
I chose D. this question is tricky but if you read it slowly and you know about sigma you'll be able to help. Thanks again.
1)Find the 20th term of the arithmetic sequence in which a1=3 and d=7.
A)143
B)136
C)140
D)133
I chose B
2)Write an equation for the nth term of the arithmetic sequence -3,3,9,15...
A)aN=n+6
B)aN=6n+9
C)aN=6n-9
D)aN=n-3
I chose B
3)Find the two arithmetic means between 4 and 22.
A)10,16
B)8,16
C)8,12
D)13,13
I chose A
4)Simplify: Find Sn for the arithmetic series in which a1=3,d=1/2,and aN=15
A)225
B)9
C)45
D)210
I chose B
5)ok this one's tricky to type but its with sigma so here it is.
There is a sigma sign and there is an 8 on the top of it and k=3 below. In parentheses to the right is (40-3k) and the question is Find.
A)45
B)282
C)-90
D)141
I chose D. this question is tricky but if you read it slowly and you know about sigma you'll be able to help. Thanks again.
Answers
Answered by
Reiny
Your #2 and 4 are not correct
#2:
you picked B which is t<sub>n</sub> = 6n+9
if you let n=1 you get 15 as your first term, you should obtain -3
doesn't C give you that result?
#4:
t<sub>n</sub> = 15
15 = 3 + (n-1)(1/2)
12 = (n-1)/2
24 = n-1
n=25
So S<sub>25</sub> = 25/2[6 + 24(1/2)]
= 25/2[18]
= 225 which is A
#2:
you picked B which is t<sub>n</sub> = 6n+9
if you let n=1 you get 15 as your first term, you should obtain -3
doesn't C give you that result?
#4:
t<sub>n</sub> = 15
15 = 3 + (n-1)(1/2)
12 = (n-1)/2
24 = n-1
n=25
So S<sub>25</sub> = 25/2[6 + 24(1/2)]
= 25/2[18]
= 225 which is A
Answered by
Jon
ok thanks. Did you check the others?
Answered by
Reiny
the others were ok
There are no AI answers yet. The ability to request AI answers is coming soon!