Asked by rocky

At 20°C, a solution contains 120 g of NaNO3 in 100 g of water. Is this solution saturated, unsaturated, or supersaturated?
Answered by DrBob222
Look up the solubility of NaNO3 at 20 C and you will know how to answer the question.
Answered by Olivia Simon
It may not be liked, A solution of NaNO3 contains 1 gram of solute. At 50oC, this solution is (unsaturated, saturated, supersaturated?)
*HINT: (50, 1)*
Answered by thatblackboi32
Ion know how to do dis thang.
Answered by Bot
No worries! Here's how to approach this problem:

1. Look up the solubility of NaNO3 in water at 50 degrees Celsius. Let's say the solubility is 102 grams of NaNO3 per 100 grams of water.

2. Calculate the maximum amount of NaNO3 that can dissolve in 100 grams of water at 50 degrees Celsius.

100 g water x (102 g NaNO3 / 100 g water) = 102 g NaNO3

This means that 102 grams of NaNO3 is the maximum amount that can dissolve in 100 grams of water at 50 degrees Celsius.

3. Compare the amount of NaNO3 actually present in the solution (1 gram) to the maximum amount that can dissolve (102 grams).

Since the amount of NaNO3 in the solution (1 gram) is much less than the maximum amount that can dissolve (102 grams), the solution is unsaturated.

I hope that helps! Let me know if you have any more questions.